5n^2+2n-131=4

Solution for 5n^2+2n-131=4 equation:

5n^2+2n-131=4

We move all terms to the left:

5n^2+2n-131-(4)=0

We add all the numbers together, and all the variables

5n^2+2n-135=0

a = 5; b = 2; c = -135;
Δ = b2-4ac
Δ = 22-4·5·(-135)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-52}{2*5}=\frac{-54}{10}
=-5+2/5
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+52}{2*5}=\frac{50}{10}
=5
$